Which particle results from the dissociation of NaCl in a solution?

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Multiple Choice

Which particle results from the dissociation of NaCl in a solution?

Explanation:
When sodium chloride (NaCl) is dissolved in water, it undergoes a process called dissociation. During dissociation, the ionic compound separates into its constituent ions. Sodium chloride is composed of sodium ions (Na⁺) and chloride ions (Cl⁻). In an aqueous solution, the polar water molecules interact with the ionic bonds between the sodium and chloride ions. The positive ends of water molecules are attracted to the negatively charged chloride ions, while the negative ends are attracted to the positively charged sodium ions. This interaction effectively pulls the ions apart, leading to the formation of free-moving cations (Na⁺) and anions (Cl⁻) in the solution. Thus, the correct answer clearly indicates that both types of ions, cations and anions, are formed during this dissociation process, resulting in a solution containing both Na⁺ and Cl⁻ ions.

When sodium chloride (NaCl) is dissolved in water, it undergoes a process called dissociation. During dissociation, the ionic compound separates into its constituent ions. Sodium chloride is composed of sodium ions (Na⁺) and chloride ions (Cl⁻).

In an aqueous solution, the polar water molecules interact with the ionic bonds between the sodium and chloride ions. The positive ends of water molecules are attracted to the negatively charged chloride ions, while the negative ends are attracted to the positively charged sodium ions. This interaction effectively pulls the ions apart, leading to the formation of free-moving cations (Na⁺) and anions (Cl⁻) in the solution.

Thus, the correct answer clearly indicates that both types of ions, cations and anions, are formed during this dissociation process, resulting in a solution containing both Na⁺ and Cl⁻ ions.

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